For dissolution endothermic with positive ΔS, how does ΔG° change with increasing temperature?

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Multiple Choice

For dissolution endothermic with positive ΔS, how does ΔG° change with increasing temperature?

Explanation:
This question hinges on how temperature affects spontaneity through Gibbs free energy. For dissolution that is endothermic and increases disorder, ΔH° > 0 and ΔS° > 0. The relationship is ΔG° = ΔH° − TΔS°. Since ΔS° is positive, the term TΔS° grows with temperature and subtracts from the positive ΔH°. At low temperatures, ΔH° dominates and ΔG° remains positive, so dissolution isn’t spontaneous. As temperature increases, TΔS° can surpass ΔH°, making ΔG° negative and dissolution spontaneous. There is a threshold temperature T = ΔH°/ΔS° where this switch occurs. Hence, the process becomes spontaneous at high temperatures.

This question hinges on how temperature affects spontaneity through Gibbs free energy. For dissolution that is endothermic and increases disorder, ΔH° > 0 and ΔS° > 0. The relationship is ΔG° = ΔH° − TΔS°. Since ΔS° is positive, the term TΔS° grows with temperature and subtracts from the positive ΔH°. At low temperatures, ΔH° dominates and ΔG° remains positive, so dissolution isn’t spontaneous. As temperature increases, TΔS° can surpass ΔH°, making ΔG° negative and dissolution spontaneous. There is a threshold temperature T = ΔH°/ΔS° where this switch occurs. Hence, the process becomes spontaneous at high temperatures.

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