For the reaction A + B → C + D, rate law is first order in [A] and second order in [B]. If [A] is halved and [B] is doubled, the rate of the reaction will

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Multiple Choice

For the reaction A + B → C + D, rate law is first order in [A] and second order in [B]. If [A] is halved and [B] is doubled, the rate of the reaction will

Explanation:
Rate depends on concentrations as rate ∝ [A]¹[B]². If A is halved, that factor contributes 1/2 to the rate. If B is doubled, because the reaction is second order in B, that contributes 2² = 4 to the rate. Multiply these effects: (1/2) × 4 = 2. The rate becomes twice its original value. Constant k cancels out in comparing the two rates, so the change comes purely from how the concentrations change with the given orders.

Rate depends on concentrations as rate ∝ [A]¹[B]². If A is halved, that factor contributes 1/2 to the rate. If B is doubled, because the reaction is second order in B, that contributes 2² = 4 to the rate. Multiply these effects: (1/2) × 4 = 2. The rate becomes twice its original value. Constant k cancels out in comparing the two rates, so the change comes purely from how the concentrations change with the given orders.

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