In copper plating from a Cu2+-containing solution, which half-reaction occurs at the cathode?

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Multiple Choice

In copper plating from a Cu2+-containing solution, which half-reaction occurs at the cathode?

Explanation:
In electroplating, the cathode is where reduction occurs, so copper ions in the solution gain electrons and deposit as solid copper on the surface. The appropriate half-reaction is Cu2+ + 2 e- → Cu(s). This is why a copper coating forms on the object being plated. The other possibilities would involve oxidation or would not occur under typical aqueous plating conditions. Oxidation of copper to Cu2+ happens at the anode, not the cathode. Oxidation of iodide to I2 is also an anodic process. Reduction of Na+ to Na(s) would require conditions that aren’t compatible with an aqueous copper-plating bath (water would be reduced to H2 well before sodium metal could form). So the cathodic process you expect here is the reduction of copper ions to metallic copper.

In electroplating, the cathode is where reduction occurs, so copper ions in the solution gain electrons and deposit as solid copper on the surface. The appropriate half-reaction is Cu2+ + 2 e- → Cu(s). This is why a copper coating forms on the object being plated.

The other possibilities would involve oxidation or would not occur under typical aqueous plating conditions. Oxidation of copper to Cu2+ happens at the anode, not the cathode. Oxidation of iodide to I2 is also an anodic process. Reduction of Na+ to Na(s) would require conditions that aren’t compatible with an aqueous copper-plating bath (water would be reduced to H2 well before sodium metal could form).

So the cathodic process you expect here is the reduction of copper ions to metallic copper.

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