In the electrolysis of molten sodium iodide, which species is oxidized at the anode?

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Multiple Choice

In the electrolysis of molten sodium iodide, which species is oxidized at the anode?

Explanation:
At the anode, oxidation occurs. In molten NaI, the only species available to be oxidized are the iodide ions. They lose electrons to form diatomic iodine: 2 I− → I2 + 2 e−. This is the oxidation happening at the anode, which is why iodide becomes iodine. Other possibilities would require reducing the cation at the cathode (Na+ to Na) or involve reactions that aren’t available in this molten-salt system (I2 gaining electrons to form I− is reduction, not oxidation). Since the question asks what is oxidized at the anode, iodide to iodine is the correct description.

At the anode, oxidation occurs. In molten NaI, the only species available to be oxidized are the iodide ions. They lose electrons to form diatomic iodine: 2 I− → I2 + 2 e−. This is the oxidation happening at the anode, which is why iodide becomes iodine.

Other possibilities would require reducing the cation at the cathode (Na+ to Na) or involve reactions that aren’t available in this molten-salt system (I2 gaining electrons to form I− is reduction, not oxidation). Since the question asks what is oxidized at the anode, iodide to iodine is the correct description.

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